c# - Debugger stops after async HttpClient.GetAsync() call in visual studio -

i'm trying test follwing http request method

public async task<httpcontent> get(string url)     {         using (httpclient client = new httpclient()) // breakpoint         using (httpresponsemessage response = await client.getasync(url)) // can't reach below point         using (httpcontent content = response.content)         {             return content;         }     } 

however, debugger seems skipping code below 2nd comment. i'm using visual studio 2015 rc, ideas? tried checking tasks window , saw nothing

edit: found solution

using system; using system.net.http; using system.threading.tasks;  namespace consoletests {     class program     {         static void main(string[] args)         {             program program = new program();             var content = program.get(@"http://www.google.com");             console.writeline("program finished");         }          public async task<httpcontent> get(string url)         {             using (httpclient client = new httpclient())             using (httpresponsemessage response = await client.getasync(url).configureawait(false))             using (httpcontent content = response.content)             {                 return content;             }         }     } } 

turns out because c# console app ended after main thread ends guess, because after adding console.readline() , waiting bit, request did return. guessed c# wait until task execute , not end before it, suppose wrong. if elaborate on why happened nice.

when main exits, program exits. outstanding asynchronous operations canceled , results discarded.

so, need block main exiting, either blocking on asynchronous operation or other method (e.g., calling console.readkey block until user hits key):

static void main(string[] args) {   program program = new program();   var content = program.get(@"http://www.google.com").wait();   console.writeline("program finished"); } 

one common approach define mainasync exception handling well:

static void main(string[] args) {   mainasync().wait(); }  static async task mainasync() {   try   {     program program = new program();     var content = await program.get(@"http://www.google.com");     console.writeline("program finished");   }   catch (exception ex)   {     console.writeline(ex);   } } 

note blocking on asynchronous code considered bad idea; there few cases should done, , console application's main method happens 1 of them.