regex - I changed repetitive awk expressions into one function -


i had 8 awk expressions differed 2 patterns searching for. created awk function improve code, wont work. doing is...

printfmt () {     awk -v mypath="$mypath" -v file_ext="$file_ext" -v name_of_file="$name_of_file" -v date="$date" -v pattern="$1" -v search="$2" '         $0 ~ pattern {             rec = $1 ofs $2 ofs $4 ofs $7             (i=9; i<=nf; i++) {                 rec = rec ofs $i                 if ($i ~ search) {                     break                 }             }         print rec >> "'$mypath''$name_of_file''$date'.'$file_ext'"     } ' "$file_location" }

and calling printfmt "$stored_procs_finished" "/([01])/". code above except instead of search /([01])/. there syntax missing?

do , read book effective awk programming, 4th edition, arnold robbins:

printfmt () {     awk -v regexp1="$1" -v regexp2="$2" '         $0 ~ regexp1 {             rec = $1 ofs $2 ofs $4 ofs $7             (i=9; i<=nf; i++) {                 rec = rec ofs $i                 if ($i ~ regexp2) {                     break                 }             }         print rec     } ' "$file_location" >> "${mypath}${name_of_file}${date}.${file_ext}" }  printfmt "$stored_procs_finished" "[01]"

your use of all-caps variable names bad - that's exported shell variables only.

don't use word "pattern" it's ambiguous, , "search" meaningless - come 2 meaningful names variables named regexp1 , regexp2.


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