C++ ordering of || and && when testing eqaulity in if statement -

this simple one, can't find answer for.

i'm trying write function returns bool when passed 2 chars of left has higher precedence.

i can achieve required functionality following:

bool precedence(char lhs, char rhs) {   if ((lhs == '*' || lhs == '/') && (rhs == '+' || rhs == '-'))     return true;   return false; } 

which fine , dandy why how isn't following same:

bool precedence(char lhs, char rhs) {   if ((lhs == ('*' || '/')) && (rhs == ('+' || '-')))     return true;   return false; } 

i know wrong, why? me both read indentically. sorry know stupid it's driving me mad.

c++ doesn't define logical operators that.

lhs == ('*' || '/') not mean lhs equals * or /, returns true if lhs 1.

the ('*' || '/') subexpression evaluates true unconditionally, because boolean logic on chars analogous checking if 0 or not. expression looks lhs == true, or lhs == 1.