BASH: determine which of three strings is in a file -

i need determine of 3 strings found in file. guaranteed 1 of 3 found in file. want different thing based on of 3 in file.

i trying do:

myfile="/home/directory/file.xml" case "stringone" in     *$myfile*)     #do thing     ;; esac case "stringtwo" in     *$myfile*)     #do thing b     ;; esac case "stringthree" in     *$myfile*)     #do thing c     ;; esac 

however, not working, , program gets stuck. there better way, or quick way fix way?

since file guaranteed contain 1 of them, can find 1 , use case statements:

myfile="/home/directory/file.xml" str=$(grep -o -m 1 -e 'stringone|stringtwo|stringthree' $myfile)  [[ -z ${str} ]] && { echo "no match found!"; exit 1; }  case "${str}" in     stringone)        #do thing        ;;      stringtwo)        #do thing b        ;;      stringthree)        #do thing c        ;;  esac 

grep options:

• -o print matching word. know word there in input file.
• -m 1 ensure stops @ first match. doesn't need scan rest of file.
• -e regex match match match either 1 of 3 strings.