For loop scans one less time in c -

the user enters string of characters, before enter size of string. have read , count how many times each letter entered.

here code:

#include <stdio.h>  char ab[] = {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'}; //size = 26  int main(void) {    int i, j, size, counter[26];   char temp;    for(i=0; i<26; i++)   {        counter[i]=0;   }    scanf("%d",&size);    for(i=0; i<size; i++)   {     scanf("%c",&temp);      for(j=0; j<26; j++)     {           if(ab[j]==temp)           {             counter[j]++;               break;           }       }   }    for(i=0; i<26; i++)    {       printf("we have %d %c\n",counter[i],ab[i]);   }    return 0;  } 

and here problem:
in given code loop reads executes 1 last time. example if enter 7 execute 6 times instead of 7 if starts 0. know problem is?

for(i=0; i<size; i++){ 

will loop 7 times when size 7.

your problem follows:

you enter number for

scanf("%d",&size); 

and press enter. above scanf scans number , leaves newline character('\n') in standard input stream. in first iteration of first loop,

scanf("%c",&temp); 

sees newline character , consumes thus, making think loop executes 1 less time. can verify adding

printf("got '%c'", temp); 

after scanf in loop.

fix using

scanf(" %c",&temp); 

the space before %c discards whitespace characters including none until first non-whitespace character.