html - Javascript - Find all occurences of brackets in a string and replace the content depending on it's content -


i want search occurrences of url() in string , replace content on basis of it's content.

so example there are these different url-contents:

url("assets/images/pic.jpg") url('assets/images/pic.jpg') url("../images/pic.jpg") url(../images/pic.jpg) url('../images/pic.jpg') url('http://website.com/images/pic.jpg')

and link should inserted in front of url, depending on content:

link = "file://dir/first/"

if there ../ in front url, should removed , link should in front of it.

and if there http:// in front, of http-link should removed, except fil @ end , link should inserted in front:

so following link should transformed to:

url('http://website.com/images/pic.jpg') url("file://dir/first/pic.jpg")

the problem is, link in between ", ' or nothing.

i know how replace ../-things

response=response.replace(/url\(\'\.\.\//g, "url('"+link); response=response.replace(/url\(\"\.\.\//g, 'url("'+link); response=response.replace(/url\(\.\.\//g, "url("+link);

does know solution?

thanks!

you may try if want touch first 2 statements.

string.replace(/(url\(['"]?)(?:\.\.\/|http:\/\/[^)]*\/)?/g, "$1" + link);

if don't want touch first 2 remove optional quantifier ? present @ last.

string.replace(/(url\(['"]?)(?:\.\.\/|http:\/\/[^)]*\/)/g, "$1" + link);

demo


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