How to display an image $_FILE on PHP -


i have code here handles upload of images.

however reason $file_destination variable unrecognize outsizde ifs statements. want attain output $file_destination variable inside tag. when use variable wont work outside.

//file uploading codes (need inside function)      global $file_destination;      if(isset($_files['file'])){         $file = $_files['file'];         print_r($file);         // file properties         $file_name = $file['name'];         $file_tmp = $file['tmp_name'];         $file_size = $file['size'];         $file_error = $file['error'];          //file extension          $file_ext = explode('.', $file_name);         $file_ext = strtolower(end($file_ext));          //check file type allowed         $allowed = array('png', 'jpg');          if(in_array($file_ext, $allowed)){             if($file_error === 0){                 if($file_size <= 2097152){                     $file_name_new = uniqid('', true). '.'.$file_ext;                     $file_destination = 'c:/'.$file_name_new;                      if(move_uploaded_file($file_tmp, $file_destination)){                         echo $file_destination;                     }                 }             }         }     }  echo <img src="<?php $file_destination ?>">

it wont work since $file_destination doesnt recognize. idea?

maybe problem security of browser. browser dont let show localfiles hd: c:/myimages.jpg

try point "src" resource (image file) in web server:

example: <img src="http://localhost/myimages.jpg">


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