bash - IF clause construction over awk command in UNIX -

i need run ls -l command , extract modification date of files. then, compare actual date, and, if not equal (ie. file hadn´t been updated on current day), extract filename file. here got far:

data1=`date | awk '{print $2}'` data2=`date | awk '{print $3}'` ls -l <file_path> | awk '{  if ( $data1 != $6 && $data2 -ne $7 ); echo "founded" }' | wc -l 

i´ve extracted month , day current date, compared month , day list command, , i'm doing word count check number of files hadn´t been updated, before add redirecting command filenames new file.

the problem if clause isn´t processing way should.

notes:

• $6 month, it´s string
• $7 day of month, it´s numerical char
• i´m using red hat 5.8 bash

as noted in comments, give files more 24 hours old:

find pattern -type f -mtime +1 

this older midnight local time if you'd prefer full day of age:

find pattern -type f -mmin +$(($(date +"%h*60+%m")))