python - Filling an array with missing contigous numbers and getting the index -

having list (no repeated values):

[67000, 67002, 67003, 67004, 67005, 67006, 67009] 

i want fill list contigous numbers missing on it, desired output be:

[67000, 67001, 67002, 67003, 67004, 67005, 67006, 67007, 67008, 67009] 

and index of items have been added list:

indx_list = [1,7,8] 

this try:

lista_num = [67000, 67002, 67003, 67004, 67005, 67006, 67009] in xrange(len(lista_num)-1):     if lista_num[i] != lista_num[i+1]-1:         print lista_num[i]         lista_n = lista_num[i]         lista_nu = lista_num[i+1]          while lista_n < lista_nu-1:             lista_n = lista_n + 1             lista_num.insert(i+1, lista_n)     else:         print "ok" 

but i'm getting following output, not desired output. think i'm messing indexes.

[67000, 67001, 67002, 67003, 67004, 67005, 67006, 67009] 

i haven't tried part of getting index of items first step of getting contigous number list not working.

how can fix code , archieve goal? in advance.

suppose original list is

a = [67000, 67002, 67003, 67004, 67005, 67006, 67009] 

so required target list can found with

out = range(min(a), max(a) + 1) 

and added indices can found with

[i (i, v) in enumerate(out) if v not in a] 

(the complexity of last line quadratic; reduce linear, can do

sa = set(a) [i (i, v) in enumerate(out) if v not in sa] 

.)