Swift's openURL method does not place a phone call with an Asterix sign (iOS 8.4) -


i'm trying place phonecall in swift application. works pretty simple regular phone numbers using openurl method. however, when try use string contains asterix (for example, dial number (****02), method returns false. i've tried using string literals no help.

is possible @ all? thanks!

    var url:nsurl = nsurl(string: "tel://****02")!     uiapplication.sharedapplication().openurl(url)

phone links

... prevent users maliciously redirecting phone calls or changing behavior of phone or account, phone app supports most, not all, of special characters in tel scheme. specifically, if url contains * or # characters, phone app not attempt dial corresponding phone number. ...


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