bash - Putting awk in a function -

i have 4 awks similiar want put them in function. awk code is...

awk -v mypath="$mypath" -v file_ext="$file_ext" -v name_of_file="$name_of_file" -v date="$date" -v pattern="$stored_procs_begin" '         $0 ~ pattern {             rec = $1 ofs $2 ofs $4 ofs $7             (i=9; i<=nf; i++) {                 rec = rec ofs $i                 if ($i ~ /\([01]\)/) {                     break                 }             }             print rec >> "'$mypath''$name_of_file''$date'.'$file_ext'"         }     ' "$file_location" 

so pattern , regular expression differ. how can put awk in function can replace pattern $1 , /([01])/ $2 if use in awk?

edit: thinking can do...

 printfmt(){    awk -v .......      $0 ~ patten {         rec..         for..            rec..            if($i ~ search)                break  print rec 

then call printfmt set?

    } 

not sure problem since have in code need maybe simplifying bit:

$ cat tst.sh function prtstuff() {     awk -v x="$1" 'begin{ print x }' }  prtstuff "foo" prtstuff "---" prtstuff "bar"  $ ./tst.sh foo --- bar