equality - Bound function object identity in Python -

this bit of python has me puzzled.

class my_class(object):     def f():         return 1 c = my_class() f1 = c.f f2 = c.f assert not f1 f2 assert id(f1) != id(f2) assert f1 == f2 

all 3 asserts pass. first 2 equivalent each other, expected both fail.

this seems strange me. python creating new, bound, member function objects whenever call c.f? why that?

ok - looking here, guess answer first question yes. still, business of having different ids consistent == seems strange in context. containers, sure, want divergence between is , == (i.e 2 distinct container objects contain equivalent data). member functions, seems is , == ought equivalent.

can motivate bit of python design me?

edit : upon further reflection, makes sense me. in order memory footprint of object small, bound functions have created upon request, , distinct objects each request.