passing char array as function parameters in C -

i want copy arr2 arr , pass arr function paramater

void func(char * array) {}  int main(void) {     int a;     char arr[6][50];     char arr2[][50]={"qweeeaa","bbbb","ffaa","eeaa","aaaa","ffaa"};      for(a=0; a<6;a++)     {         strcpy(arr[a], arr2[a]);     }      func(arr);      return 0; } 

but can not pass arr function parameter.

[warning] passing argument 1 of 'func' incompatible pointer type [enabled default] [note] expected 'char *' argument of type 'char (*)[50]' 

i using mingw gcc 4.8.1

the type pass , type function expects not match. change function receive pointer array:

void func(char (*array)[50]) {  } 

other problems:

1) haven't declared prototype func() either. in pre-c99 mode, compiler assume function returns int , cause problem. in c99 , c11, missing prototype makes code invalid. either declare prototype @ top of source file or move function above main().

2) include appropriate headers (<stdio.h> printf etc).